/ [r!(n - r)!] Now, to determine the number of 6-card hands containing at least one copy of the card you desire, you use: nCr(copies of card, # in starting hand) x nCr((cards in deck - copies of card), (cards being drawn - # in starting hand)) nCr(copies of card, # in starting hand) x nCr(cards in deck - copies of card), (cards being drawn - # in starting hand)) nCr(3,1) x nCr(40-3,6-1) + nCr(3,2) x nCr(40-3,6-2) + nCr(3,3) x nCr(40-3,6-3) = 1,513,596 That determines the possibility of drawing one, two, or three copies of the card in your starting hand
RRC - Crimson Blast Discard all Fire Energy from this Pokmon
"But it's a bit different because, at the end of the day, it's a business where you have to profit or else you're done." The shop has already become a gathering place for collectors of all ages
Currently, unsure what my approach should be for the deck cards